16x^2-84x-190=0

Solution for 16x^2-84x-190=0 equation:

16x^2-84x-190=0

a = 16; b = -84; c = -190;
Δ = b2-4ac
Δ = -842-4·16·(-190)
Δ = 19216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19216}=\sqrt{16*1201}=\sqrt{16}*\sqrt{1201}=4\sqrt{1201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-4\sqrt{1201}}{2*16}=\frac{84-4\sqrt{1201}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+4\sqrt{1201}}{2*16}=\frac{84+4\sqrt{1201}}{32}
$